Question

A square lead slab of side 50 cm and thickness 10 cm is subjected to a shear force of 9x10^4 N. The lower edge is riveted to the floor, how much is the upper edge displaced if the shear modulus of rubber is 5.6x10^9 Pa.

Answer 1

Dear Student,

Shear modulus is
$$\begin{gathered} {\gamma }_s=\frac{{\displaystyle \frac{F}{A}}}{{\displaystyle \frac{∆x}{l}}} \\ F:\tan gentialforce \\ Aareaonwhich\tan gentialforceact. \\ ∆x:transversedisplacement. \\ l:initoallength \\ pluginthevalues. \\ ∆x=\frac{90000*0.1}{0.5*0.5*5.6*{10}^9}=6.428*{10}^{-6}m \\ Regards \end{gathered}$$