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Question

A square loop of conducting wire is placed near a long straight current carrying wire as shown. Match the statements in column-I with the corresponding results in column-II.

Column IColumn II(a)If the magnitude of currentI (p)Induced current in is increasedthe loop will be clockwise(b)If the magnitude of current I(q)Induced current in theis decreasedloop will be anticlockwise(c)If the loop is moved(r)wire will attract the loopaway from the wire(d)If the loop is moved(s)wire will repel the loop(t)Torque about center of mass ofloop is zero due to magnetic force


A
(A)-s; (B)-r; (C)-r; (D)-s
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B
(A)-r; (B)-r; (C)-s; (D)-s
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C
(A)-s; (B)-r; (C)-r; (D)-s
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D
(A)-s; (B)-s; (C)-s; (D)-r
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Solution

The correct option is C (A)-s; (B)-r; (C)-r; (D)-s
A) Due to current carrying wire, the magnetic field in loop will be inwards w.r.t the paper. As current is increased, magnetic flux associated with loop increases. So a current will be induced so as to decrease magnetic flux inside the loop. Hence induced current in the loop will be anticlockwise. The current in left side of loop shall be downwards and hence repelled by wire. The current in right side of loop is upwards and hence attracted by wire. Since left side of loop is nearer to wire, repulsive force will dominate. Hence wire will repel the loop
(B) Options in (B) will be opposite of that in (A)
(C) When the loop is moved away from wire, magnetic flux decreases in the loop. Hence the options for this case shall be same as in (B)
(D) When the loop is moved towards the wire, magnetic flux increases in the loop. Hence the options for this case shall be same as in (A)

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