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Question

A square loop of side 4 cm is lying on a horizontal table. A uniform magnetic field of 0.5 T is directed downwards at an angle of 60o to the vertical as shown in Fig. 25.3. If the field increases from zero to its final value in 0.2 s, the emf induced in the loop will be


A

1 mV

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B

2 mV

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C

3 mV

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D

4 mV

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Solution

The correct option is B

2 mV


Area of the square loop (A) = (4×10(2))2=1.6×103m2. Magnetic flux ϕ=AB cos θ, where B cos θ is the component of the magnetic field perpendicular to the plane of the loop, Therefore, change in flux is
Δϕ=A B cos θ=1.6×103×0.5×cos 60o=0.4×103WbInduced emf e=ΔϕΔt=0.4×1030.2=2×103 V=2 mV.


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