A square loop of side 6 cm carries a current of 30 A- Calculate the magnitude of magnetic field B- at a point P lying on the axis of the loop and a distance -7 cm from centre of the loop-

r=√(9+7)=4 cm #160; #160; B=μ_o/4πi/r(2sinα) #160; #160; #160; #160; =(10^ 7)(30/4×10^ 2)(2×3/5) #160; #160; #160; # ...

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Standard XII

Physics

Rotational EMF

A square loop...

Question

A square loop of side 6 cm carries a current of 30 A. Calculate the magnitude of magnetic field $\to B$ at a point $P$ lying on the axis of the loop and a distance $\sqrt{7}$ cm from centre of the loop?

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Solution

$r = \sqrt{9 + 7} = 4 c m$
$B = \frac{μ_{o}}{4 π} \frac{i}{r} (2 s i n α)$
$= (10^{- 7}) (\frac{30}{4 \times 10^{- 2}}) (2 \times \frac{3}{5})$
$= 9.0 \times 10^{- 5} T$
Net field = $4 B s i n θ$
= $4 \times 9.0 \times 10^{- 5} \times \frac{3}{4}$
= $2.7 \times 10^{- 4} T$

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A square loop of side 6 cm carries a current of 30 A. Calculate the magnitude of magnetic field →B at a point P lying on the axis of the loop and a distance √7 cm from centre of the loop?

r=√9+7=4cm B=μo4πir(2sinα) =(10−7)(304×10−2)(2×35) =9.0×10−5TNet field = 4Bsinθ = 4×9.0×10−5×34 = 2.7×10−4T

A square loop of side 6 cm carries a current of 30 A. Calculate the magnitude of magnetic field $\to B$ at a point $P$ lying on the axis of the loop and a distance $\sqrt{7}$ cm from centre of the loop?

$r = \sqrt{9 + 7} = 4 c m$
$B = \frac{μ_{o}}{4 π} \frac{i}{r} (2 s i n α)$
$= (10^{- 7}) (\frac{30}{4 \times 10^{- 2}}) (2 \times \frac{3}{5})$
$= 9.0 \times 10^{- 5} T$
Net field = $4 B s i n θ$
= $4 \times 9.0 \times 10^{- 5} \times \frac{3}{4}$
= $2.7 \times 10^{- 4} T$