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Byju's Answer
Standard XII
Physics
Magnetic Field Due to a Circular Arc at the Centre
A square loop...
Question
A square loop of side 'a' carries a current
I
.The magnetic field at the centre of the loop is
A
2
μ
o
I
√
2
π
a
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B
μ
o
I
√
2
π
a
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C
4
μ
o
I
√
2
π
a
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D
μ
o
I
π
a
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Solution
The correct option is
A
2
μ
o
I
√
2
π
a
B
c
=
4
[
μ
o
4
π
I
a
/
2
(
s
i
n
45
o
+
s
i
n
45
o
)
]
=
2
√
2
μ
o
I
π
a
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