Case A:
→B=B0^i
Force on the wire along x-axis or parallel to x-axis is zero.
Force is on wire along y-axis or parallel to y-axis.
→F=i2lB(^j×^i)=−i2lB0^k
Since there are two sides along x-axis or parallel to x-axis, net force is
→F=2×(−i2lB0^k)=−ilB0^k
Also, since since both the forces are opposite and pass through the center of the loop, net torque on the loop is zero.
Case B:
→B=B0^j
Force on the wire along y-axis or parallel to y-axis is zero.
Force is on wire along x-axis or parallel to x-axis.
→F=i2lB(^i×^j)=i2lB0^k
Since there are two sides along y-axis or parallel to y-axis, net force is
→F=2×(i2lB0^j)=ilB0^k
Also, since since both the forces are opposite and pass through the center of the loop, net torque on the loop is zero.
Case C:
It is a combination of Case A and Case B
Hence, net force and net torque on the loop is zero.
Case D:
→B=B0^j
Force on two sides along x-axis or parallel to x-axis is
→F1=ilB0(^i×^k)=−ilB0^j
Force on two sides along y-axis or parallel to y-axis is
→F2=ilB0(^j×^k)=ilB0^j
Resultant of →F1 and →F2 is →F=→F1+→F2=√2ilB01√2(^i+^j)
Torque due to →F is zero since the net force passes through the center of the loop.
A→3,4
V→3,4
C→2,3
D→1,3