A square loop of wire is placed in a magnetic field as shown below. If the direction of current flow is clockwise, what is the direction of the net force on the loop?
A
Up the page
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B
Down the page
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C
To the left
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D
To the right
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E
The net force is zero.
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Solution
The correct option is B The net force is zero. We can take four sides of square as four separate current carrying wires , if we apply Fleming's left hand rule to find the force on each side , we find that ,forces on top and bottom sides are equal and opposite (cancel each other) and forces on left and right sides are also equal and opposite , therefore net force on loop is zero .
magnetic force on top side Ft=ILBsin90=ILB (up the page ) ,
magnetic force on bottom side Fb=ILBsin90=ILB (down the page) ,
magnetic force on left side Fl=ILBsin90=ILB (to the left of the page ) ,
magnetic force on right side Fr=ILBsin90=ILB (to the right of the page )