1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A square metal wire loop of side 10 cm and of resistance 2 Ω moves with constant velocity in the presence of a uniform magnetic field of induction 4 T, perpendicular and into the plane of the loop. The loop is connected to a network of resistance as shown in the Figure. If the loop should have a steady current of 2 mA, the speed of the loop must be (in cm s−1) :

A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 2As this is wheatstore bridge.Req=6×36+3=2ΩTotalresistance=2+2=4ΩNow steady current is 2mA∴ Voltage required =(.002)4 =0.008V=8mVB=4TE=8mV=−dϕdt=−d4(Area)dt8×10−3=4×(0.10)VV=2×10−2m/s=2cm/s

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Electric Flux
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program