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Standard XII

Physics

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A square meta...

Question

A square metal wire loop of side 10 cm and resistance $1 Ω$ is moved with a constant velocity $v_{0}$ in a uniform magnetic field of induction B = 2 $w e b e r / m^{2}$ as shown in the figure. The magnetic field lines are perpendicular to the plane of the loop (directed into the paper). The loop in connected to a network of resistors each of value $3 Ω$ . The resistances of the lead wires OS and PQ are negligible. What should be the speed of the loop so as to have a steady current of 1 mA in the loop?

0.02m/s

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2 m/s

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20 m/s

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200 m/s

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Solution

The correct option is A 0.02m/s
Total resistance $R^{'} = 1 + \frac{6}{2} = 4 R$
$E = R^{'} I$
$= 4 \times 1 \times 10^{- 3} V$
$= 4 m V$
$E = B l V_{0}$
$4 \times 10^{- 3} = 2 \times 10 \times 10^{- 2} V_{0}$
$V_{0} = 2 \times 10^{- 2} = 0.02 m s^{- 1}$

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The correct option is A 0.02m/sTotal resistance R′=1+62=4R E=R′I =4×1×10−3V =4mV E=B l V0 4×10−3=2×10×10−2V0 V0=2×10−2=0.02ms−1

The correct option is A 0.02m/s
Total resistance $R^{'} = 1 + \frac{6}{2} = 4 R$
$E = R^{'} I$
$= 4 \times 1 \times 10^{- 3} V$
$= 4 m V$
$E = B l V_{0}$
$4 \times 10^{- 3} = 2 \times 10 \times 10^{- 2} V_{0}$
$V_{0} = 2 \times 10^{- 2} = 0.02 m s^{- 1}$