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Standard XII

Physics

Rotational EMF

A square meta...

Question

A square metal wire loop of side $10 c m$ is moved with a constant velocity $v$ in a uniform magnetic field $B = 2 W b m^{- 2}$ as shown in figure. The magnetic field lines are perpendicular to the plane of the loop and directed into the plane. The loop is connected to the network of resistances, each of value $3 Ω$ . The resistance of the other wires are negligible. The speed of the loop so as to have a steady current of $1 m A$ in the loop is

1 c m s^{- 1}

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4 c m s^{- 1}

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1.5 c m s^{- 1}

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0.5 c m s^{- 1}

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Solution

The correct option is C $1.5 c m s^{- 1}$
Let the speed of the rod be $v$
$ϵ = B v l = 2 \times 0.1 v$
$ϵ = 0.2 v$

Since the above network is a wheatstone bridge,
Therefore total resistance is $R = 3 Ω$
Now current is given as $10^{- 3} m A$
$10^{- 3} = \frac{0.2 v}{R}$
$10^{- 3} = \frac{0.2 v}{3}$
$v = 1.5 c m s^{- 1}$
For detailed solution watch the next video.

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The correct option is C 1.5 cms−1Let the speed of the rod be v ϵ=Bvl=2×0.1v ϵ=0.2v Since the above network is a wheatstone bridge, Therefore total resistance is R=3 Ω Now current is given as 10−3 mA 10−3=0.2vR 10−3=0.2v3 v=1.5 cms−1 For detailed solution watch the next video.