A square metallic frame has perimeter 308 cm. It is bent in the shape of a circle. Find the area of the circle so formed

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Solution

Dear student,

The perimeter of the square equals the circumference of the circle.
Let the radius of the circle be r
$2 π r = 308 2 \times \frac{22}{7} \times r = 308 r = \frac{308 \times 7}{2 \times 22} r = 49$
Area of the circle = $π r^{2} = \frac{22}{7} \times 49 \times 49 = 7546 c m^{2}$

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A square metallic frame has perimeter 308 cm. It is bent in the shape of a circle. Find the area of the circle so formed

Dear student, The perimeter of the square equals the circumference of the circle. Let the radius of the circle be r 2πr=3082×227×r=308r=308×72×22r=49 Area of the circle = πr2=227×49×49=7546 cm2

Dear student,

The perimeter of the square equals the circumference of the circle.
Let the radius of the circle be r
$2 π r = 308 2 \times \frac{22}{7} \times r = 308 r = \frac{308 \times 7}{2 \times 22} r = 49$
Area of the circle = $π r^{2} = \frac{22}{7} \times 49 \times 49 = 7546 c m^{2}$