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Byju's Answer

Standard XII

Physics

Motional EMF

A square meta...

Question

A square metallic wire loop of side 0.1 m and resistance of $1 Ω$ is moved with a constant velocity in a magnetic field of $2 w b / m^{2}$ as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

1 cm/sec

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2 cm/sec

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3 cm/sec

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4 cm/sec

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Solution

The correct option is B 2 cm/sec
Equivalent resistance of the given Wheatstone bridge circuit (balanced) is $3 Ω$ so total resistance in circuit is $R = 3 + 1 = 4 Ω$ . The emf induced in the loop e=Bvl.
So induced current $i = \frac{e}{R} = \frac{B v l}{R}$
$\Rightarrow 10^{- 3} = \frac{2 \times v \times (10 \times 10^{- 2})}{4} \Rightarrow v = 2 c m / s e c .$

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The correct option is B 2 cm/secEquivalent resistance of the given Wheatstone bridge circuit (balanced) is 3Ω so total resistance in circuit is R=3+1=4Ω. The emf induced in the loop e=Bvl. So induced current i=eR=BvlR ⇒ 10−3=2×v×(10×10−2)4⇒v=2cm/sec.