A square piece of tin of side 18 cm is to be made into a box without top by cutting a square from each corner and folding up the flabs to form the box. What should be the side of the square to be out off so that the volume of the box is the maximum possible.
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Solution

For maximum volume, we need to consider complete area of piece of tin.
Let the side of the new cube be x. So, there will be of 5 square so area of 5 square will be $5 x^{2}$
$5 x^{2} = 18 \times 18$ (sum of tin plate)
$x = \sqrt{\frac{18 \times 18}{5}}$
$= 8.049$

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A square piece of tin of side 18 cm is to be made into a box without top by cutting a square from each corner and folding up the flabs to form the box. What should be the side of the square to be out off so that the volume of the box is the maximum possible.undefinedundefinedundefinedundefined

For maximum volume, we need to consider complete area of piece of tin. Let the side of the new cube be x. So, there will be of 5 square so area of 5 square will be 5x2 5x2=18×18 (sum of tin plate) x=√18×185 =8.049

A square piece of tin of side 18 cm is to be made into a box without top by cutting a square from each corner and folding up the flabs to form the box. What should be the side of the square to be out off so that the volume of the box is the maximum possible.
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For maximum volume, we need to consider complete area of piece of tin.
Let the side of the new cube be x. So, there will be of 5 square so area of 5 square will be $5 x^{2}$
$5 x^{2} = 18 \times 18$ (sum of tin plate)
$x = \sqrt{\frac{18 \times 18}{5}}$
$= 8.049$