A square plate of mass M and edge L is shown in the fig. The moment of inertia of the plate about the axis in the plane of plate and passing through one of its vertex making an angle 150 with the horizontal is
A
ML212
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B
11ML224
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C
7ML212
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D
none of these
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Solution
The correct option is B11ML224 From the figure we have AO=L√2 Thus we get the perpendicular distance between the axis about which the plate is rotated and the center of mass as AN=L√2cos30o=L√32√2 Now we have IPP′=ML212 Thus using parallel axis theorem we get the moment of inertia about the given axis as 11ML224