A square section of side 20cm is removed from the bigger square of side 40cm as shown in the figure. Find the center of mass of the remaining portion of the square.
A
(504,504)cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(25,25)cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(503,503)cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(20,20)cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C(503,503)cm
COM of square ABCD is (x1,y1)=(20,20)cm COM of square EFGC is (x2y2)=(30,30)cm
Let the mass of square ABCD be M. Since, the area of square EFGC is one fourth of square ABCD, the mass of the removed square EFGC is M4. So, take m1=M and m2=−M4
X-coordinate of COM of remaining portion, xCOM=m1x1−m2x2m1−m2=M(20)−M4(30)M−M4 =20−30434=503cm
Y-coodinate of COM of remaining portion, yCOM=m1y1−m2y2m1−m2=M(20)−M4(30)M−M4 =20−30434=503cm
So, position of COM of remaining portion is (503,503)cm