Question

A square surface of side L meter in the plane of the paper is placed in a uniform electric field E(volt/m) acting along the same plane at an angle with the horizontal side of the square as shown in figure. The electric flux linked to the surface,in units of volt$-m$, is

• A. $E{L}^2$
• B. ${}^2\cos \theta$
• C. ${}^2\sin \theta$
• D. $Zero$

Answer 1

Answer: (D)

$Zero$

The electric flux linked to the surface is given by:

${\varphi }_E=\overrightarrow{E}.d\overrightarrow{A}$

The angle between the area vector and the field lines is ${90}^o$.

Thus,

${\varphi }_E=EAcos\theta =0$

Also,

As, there is no field line crossing the surface, the electric flux linked to the surface will be zero.