Question

A square wire loop with sides $0.5m$ is placed with its plane perpendicular to a magnetic. The resistance of the loop is $5\Omega$. Find what rate the magnetic induction should be changed so that a current of $0.1A$ is induced in the loop.

Answer 1

$i=0.1A$

$R=5\Omega$

$\Rightarrow Emf=0.1\times 5$

$=0.5=\left(\frac{d\varphi }{dt}\right)$

$\Rightarrow 0.5=A\left(\frac{dB}{dt}\right)$

$\Rightarrow \frac{dB}{dt}=\frac{0.5}{A}=\frac{0.5}{0.5\times 0.5}=2$

$\Rightarrow \frac{dB}{dt}=2Tesla/\sec .$

We get,

$\frac{dB}{dt}=2Tesla/\sec .$