A stable di-positive ion and a di-negative ion are isoelectronic with an octet configuration in the second shell of their atom. Identify the preceding and succeeding elements and write their electronic configuration.
A stable di-positive ion and a di-negative ion are isoelectronic with an octet configuration in the second shell of their atom. Identify the preceding and succeeding elements and write their electronic configuration.
Let the di-positive ion be ‘X+2 ’ and the di-negative ion is ‘Y-2’.
The octet in the second shell is 2,8.
The number of electrons in X=10 + 2=12.
The number of electrons in Y = 10 - 2 = 8.
'X' is magnesium with electronic configurations 2, 8, 2. ‘Y’ is oxygen with electronic configurations 2,6.
The element preceding magnesium is Sodium(electronic configuration 2, 8, 1) and the succeeding one is aluminium (electronic configuration 2, 8, 3).
The element preceding oxygen is nitrogen(electronic configuration 2, 5) and the succeeding one is fluorine (electronic configuration 2,7).
Let the di-positive ion be ‘X+2 ’ and the di-negative ion is ‘Y-2’.
The octet in the second shell is 2,8.
The number of electrons in X=10 + 2=12.
The number of electrons in Y = 10 - 2 = 8.
'X' is magnesium with electronic configurations 2, 8, 2. ‘Y’ is oxygen with electronic configurations 2,6.
The element preceding magnesium is Sodium(electronic configuration 2, 8, 1) and the succeeding one is aluminium (electronic configuration 2, 8, 3).
The element preceding oxygen is nitrogen(electronic configuration 2, 5) and the succeeding one is fluorine (electronic configuration 2,7).
