Question

A standard deck of cards is shuffled. What is the probability of:

• A. $P\left(BlackLettered\right)=\frac{4}{13}$
  $P\left(RedNumbered\right)=\frac{4}{13}$
  
• B. $P\left(BlackLettered\right)=\frac{9}{13}$
  $P\left(RedNumbered\right)=\frac{4}{13}$
• C. $P\left(BlackLettered\right)=\frac{4}{26}$
  $P\left(RedNumbered\right)=\frac{9}{13}$
• D. $P\left(BlackLettered\right)=\frac{2}{13}$
  $P\left(RedNumbered\right)=\frac{9}{26}$

Answer 1

The correct option is D $P\left(BlackLettered\right)=\frac{2}{13}$

$P\left(RedNumbered\right)=\frac{9}{26}$
Number of lettered cards $=16$
Number of black lettered cards $=8$

Number of numbered cards $=36$
Number of red numbered cards $=18$

Total number of cards $=52$

Therefore,
$P\left(BlackLettered\right)=\frac{8}{52}=\frac{2}{13}$

$P\left(RedNumbered\right)=\frac{18}{52}=\frac{9}{26}$