Question

A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a separation of $1.21\mathring{A}$ between them. Then wavelength of the standing wave is :

• A. $1.21\mathring{A}$
• B. $2.42\mathring{A}$
• C. $6.05\mathring{A}$
• D. $3.63\mathring{A}$

Answer 1

The correct option is A $1.21\mathring{A}$

3 node;

2 Antinode

$n=2$

$\lambda =\frac{2L}{n}$

$=\frac{2\times 1.21\times {10}^{-10}}{2}$

$\lambda =1.21\times {10}^{-10}$

$\lambda =1.21A^o$