A standing wave having $3$ nodes and $2$ antinodes is formed between two atoms having a distance $1.21 ˚ A$ between them. The wavelength of the standing wave is

1.21 ˚ A

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3.63 ˚ A

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4.84 ˚ A

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5.86 ˚ A

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Solution

The correct option is B $1.21 ˚ A$
The given situation can be shown as
Given the distance between the two atoms $= 1.21 ˚ A$
so, the wavelength of the standing wave is
$\frac{λ}{2} + \frac{λ}{2} = λ = 1.21 ˚ A$

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