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Question
A star A is 100 times brighter than star B. Then mB−mA the difference in their apparent magnitudes is:
A star A is 100 times brighter than star B. Then mB−mA the difference in their apparent magnitudes is:
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Solution
The correct option is A 5
mB−mA=−2.5log[IBIA]
=−2.5log(1100)
=−2.5[log1−log100]
=−2.5×−2
=5
mB−mA=−2.5log[IBIA]
=−2.5log(1100)
=−2.5[log1−log100]
=−2.5×−2
=5
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