Question

A star has ${10}^{40}$ deuterons. It produces energy via the process:
${}_1^{2}H{+}_1^{2}H⟶$ ${}_1^{3}H{+}_1^{1}H$
${}_1^{2}H{+}_1^{3}H⟶$ ${}_2^{4}He{+}_0^{1}n$
If the average power radiated by the star is ${10}^{16}W$, then the deuteron supply of the star is exhausted in a time of the order of:

• A. ${10}^{6}sec$
• B. ${10}^{8}sec$
• C. ${10}^{12}sec$
• D. ${10}^{16}sec$

Answer 1

The correct option is C ${10}^{12}sec$