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Lissajous Pattern-2

A stationary ...

Question

A stationary closed Lissajous pattern on an oscilloscope has 3 horizontal tangencies and 2 vertical tangencies for a horizontal input with, frequency 3 kHz. The frequency of the vertical input is,

A

1.5 kHz

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B

2 kHz

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C

3 kHz

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D

4.5 kHz

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Solution

The correct option is D 4.5 kHz
$\frac{f_{y}}{f_{x}} = \frac{H o r i z o n t a l T a n g e n c i e s}{V e r t i c a l T a n g e n c i e s}$
$\Rightarrow \frac{f_{y}}{3} = \frac{3}{2}$
$\Rightarrow f_{y} = 4.5 k H z$

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