A stationary hydrogen atom emits photon corresponding to the first time of Lyman series. If R is the Rydberg's constant and m is the mass of the atom, then the velocity acquired by the atom is (neglect energy absorbed by the photon).
A
4mRh
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B
Rh4m
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C
3Rh4m
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D
4m3Rh
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Solution
The correct option is A3Rh4m For first line of Lyman series, 1λ=R(112−122)=R(1−14)=34R Again we have momentum, p=mv or hλ=mv or v=hmλ Putting the value of λ, we have v=hm(34R)=3hR4m.