CameraIcon

SearchIcon

MyQuestionIcon

259

You visited us 259 times! Enjoying our articles? Unlock Full Access!

Linear Momentum

A stationary ...

Question

A stationary particle explodes into two particles of masses x and y which move in opposite directions with velocity v1 and v2. The ratio of their kinetic energy is

Open in App

Solution

m1v1=m2v2 (p1=p2)
E1÷E2=((1÷2)×m1×v1^2))÷((1÷2)×m2×v2^2)
=(p1^2÷(2×m1))÷(p2^2÷(2×m2))
by cancelling we get
=m2÷m1

Suggest Corrections

thumbs-up

39

Similar questions

Q. A stationary particle explodes into two particles of masses

x

y

, which move in opposite direction with velocity

v_{1}

v_{2}

. The ratio of their kinetic energies

(E_{1} : E_{2})

Q. A stationary particle explodes into two particles of masses

m_{1}

m_{2}

which move in opposite directions with velocities

v_{1}

v_{2}

. The ratio of their kinetic energies

E_{1} / E_{2}

Q. A stationary object explodes into masses

m_{1}

m_{2}

. They move in opposite directions with velocities

V_{1}

V_{2}

. The ratio of kinetic energy

E_{1}

to kinetic energy

E_{2}

Q. Example 8.28 Two particle of mass m and 2m moving in opposite directions collide elastically with velocities v and 2v Find their velocities after collision.
SOL :- Here,

v_{1} = - v, v_{2} = 2 v, m_{1} = m a n d m_{2} = 2 m

Q. A particle of mass

m_{1}

and moving with velocity

v_{1}

collides head on with another stationary particle of mass

m_{2}

elastically. If after the collision their velocities are

v_{1}

v_{2}

then under the condition

m_{1} = m_{2}

their values will be :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

PHYSICS

Watch in App

explore_more_icon

Explore more

Linear Momentum

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon