Question

A stationary wave is set on string of length $120$cm. If the distance between successive locations where amplitude of vibration of particle is $3.5$mm is $15$cm. The mode of vibration is ______, (Note: $A>3.5$ mm)

• A. Natural
• B. $2^{nd}$ harmonic
• C. Third overtone
• D. $3^{rd}$ harmonic

Answer 1

The correct option is A Natural

Here, in figure above we can see the wave where repeatation is in position of 15cm and so this wave cannot be a sine wave.

Now, as we know mode of vibration is number of half waves in the vibration.

Hence answer is Natural Mode.