Question

A steady current of 1A closed to a conductor. Calculate the number of electrons that flow through any section of the conductor for 1s.

Answer 1

Dear Student,


$$\begin{gathered} \mathrm{We}\mathrm{know}\mathrm{that}, \\ \mathrm{Q}=\mathrm{It} \\ =1\mathrm{A}\times 1\mathrm{s} \\ =1\mathrm{C} \\ \mathrm{No}.\mathrm{of}\mathrm{electrons}=\frac{\mathrm{Total}\mathrm{charge}}{\mathrm{Charge}\mathrm{on}1\mathrm{electron}} \\ =\frac{1}{1.6\times {10}^{-19}} \\ =6.25\times {10}^{18}\mathrm{electrons} \end{gathered}$$