A steady P.D. of 10V produces heat at a rate of ′x′ in a resistor. The peak value of A.C. voltage which will produce heat at the rate of x/2 in the same resistor is:
A
5V
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B
5√2V
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C
10V
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D
10√2 V
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Solution
The correct option is C10V Power P=V2rmsR DC voltage : So, V2rmsR=X ⇒100R=X ⇒R=100X AC voltage : Power P=V2rmsR where Vrms=Vmax√2 X2=V2max2R ∴100=V2max Vmax=10V.