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Question

A steam turbine receives steam steady at 10 bar with a enthalpy of 3000 kJ/kg and discharges at 1 bar with an enthalpy of 2700 kJ/kg. The work output is 250 kJ/kg. The changes in kinetic and potential energies are negligible. The heat transfer from the turbine casing to the surroundings is equal to

A
0 kJ
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B
50 kJ
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C
150 kJ
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D
250 kJ
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Solution

The correct option is B 50 kJ
(b)
p1=10bar; h1=3000kJ/kg; p2=1bar
h2=2700kJ/kg; w=250kJ/kg
q=?
The steady flow energy equation for unit mass flow rate,
h1+V212+gz1+q=h2+V212+gz2+w
Change in KE and PE are negligible
h1+q=h2+w
3000+q=2700+250
or q=50kJ/kg
The heat transfer from the turbine casing to the surroundings is equal to 50 kJ\kg.

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