A steel ball falls from a height ‘h’ on a floor for which the coefficient of restitution is e. The height attained by the ball after the first rebound is .

h e

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h e^{2}

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h / e

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h / e^{2}

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Solution

The correct option is D $h / e^{2}$
The velocity attained after a fall through a height h is given by $v^{2} = 2 g h$
Thus $h \propto v^{2}$ The velocity after first rebound is $e v$ .

Therefore, the height attained after first rebound = $h e^{2}$ .

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A steel ball falls from a height ‘h’ on a floor for which the coefficient of restitution is e. The height attained by the ball after the first rebound is .

The correct option is D h/e2The velocity attained after a fall through a height h is given by v2=2gh Thus h∝v2 The velocity after first rebound is ev. Therefore, the height attained after first rebound = he2.

The correct option is D $h / e^{2}$
The velocity attained after a fall through a height h is given by $v^{2} = 2 g h$
Thus $h \propto v^{2}$ The velocity after first rebound is $e v$ .

Therefore, the height attained after first rebound = $h e^{2}$ .