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Question

A steel ball falls from a height h on a floor for which the coefficient of restitution is e. The height attained by the ball after two rebounds is

A
eh
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B
e2h
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C
e3h
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D
e4h
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Solution

The correct option is D e4h
Ist collision
Velocity of strike =2gh
Velocity of rebound =e×2gh=u
height attained =u22g=22×2gh2g
=e2h
IInd collision
Velocity of strike =29×e2h
=e2gh
Velocity of rebound =e×(e2gh)
=e22gh=v
height attained =v22g=e4×2gh2g8e4h.

1181596_1400256_ans_e9e0f3f1965f4228b30c7e57ce29ac02.jpg

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