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Question

A steel ball is bouncing up and down on a steel plate with a period of oscillation 1 second. If g=10ms−2, then it bounces up to a height of

A
5 m
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B
10 m
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C
2.5 m
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D
1.25 m
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Solution

The correct option is D 1.25 m
The ball takes 1 second to bounce up and down through the same height; so, the time of fall is equal to time of rise i.e. 12 second.
Using second law of motion, s=ut+12at2
Height, s=h, initial velocity, u=0
h=0+12g(12)2
h=108
h=1.25m
So, the ball bounces up to a height of 1.25m.

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