Question

A steel ball of mass 'm' falls in a viscous liquid with a terminal velocity $4m{s}^{-1}$ . If another steel ball of mass 8m falls through the same liquid then its terminal velocity is

• A. $4m{s}^{-1}$
• B. $8m{s}^{-1}$
• C. $16m{s}^{-1}$
• D. $2m{s}^{-1}$

Answer 1

The correct option is A $4m{s}^{-1}$

$V=\frac{2}{q}\frac{r^{2}g\left(s-\sigma \right)}{\eta }$

$\because$ it is independent of mass$.$

$\therefore$ velocity remains unchanged

Hence,

option $\left(A\right)$ is correct answer.