A steel bar of 10×50mm is cantilevered with two M12 bolts (P and Q) to support a static load of 4kN as shown in the figure.
The primary and secondary shear loads on bolt P, respectively, are
A
20kN,0kN
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B
0kN,20kN
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C
20kN,2kN
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D
2kN,20kN
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Solution
The correct option is D2kN,20kN
⇒ Primary shear load due to P1 Pp=P1n=42=2kN ⇒ Now for secondary shear load effect of P and P2 TM=P×e=8×106N−mm Ps1r1+Ps2r2=P×e Ps1r1[r21+r21]=P×e Ps1=Ps2 r1=r2 Ps1200[2×(200)2]=8×106 Ps1=Ps2=20,000N=20kN