A steel bar of $10 \times 50 m m$ is cantilevered with two $M 12$ bolts (P and Q) to support a static load of $4 k N$ as shown in the figure.

The primary and secondary shear loads on bolt $P$ , respectively, are

20 k N, 0 k N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 k N, 20 k N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 k N, 2 k N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 k N, 20 k N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2 k N, 20 k N$

$\Rightarrow$ Primary shear load due to $P_{1}$
$P_{p} = \frac{P_{1}}{n} = \frac{4}{2} = 2 k N$
$\Rightarrow$ Now for secondary shear load effect of $P$ and $P_{2}$
$T M = P \times e = 8 \times 10^{6} N - m m$
$P s_{1} r_{1} + P s_{2} r_{2} = P \times e$
$\frac{P s_{1}}{r_{1}} [r_{1}^{2} + r_{1}^{2}] = P \times e$
$P s_{1} = P s_{2}$
$r_{1} = r_{2}$
$\frac{P s_{1}}{200} [2 \times (200)^{2}] = 8 \times 10^{6}$
$P s_{1} = P s_{2} = 20, 000 N = 20 k N$

Suggest Corrections

Similar questions

10 \times 50 m m

M 12

4 k N

P

A, B

C

6 k N

C

A cantilever bracket is bolted to a column using three M 12 \times 1.75 bolts, P, Q and R. The value of maximum shear stress developed in the bolt P (in MPa) is

Join BYJU'S Learning Program