A steel beam of breadth 120 mm and height 750 mm is loaded as shown in the figure. Assume Esteel=200Gpa.
The value of maximum deflection of the beam is
A
93.75mm
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B
83.75mm
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C
73.75mm
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D
63.75mm
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Solution
The correct option is A93.75mm Moment of inertia, I=bh312=120×(750)312=42.1875×108mm4
Maximum deflection in the beam is given by δ=5384wL4EI =5384×120×103103×(15×103)4200×103×42.1875×108 =93.75mm