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Question

A steel beam of breadth 120 mm and height 750 mm is loaded as shown in the figure. Assume Esteel=200 Gpa.

The value of maximum deflection of the beam is

A
93.75 mm
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B
83.75 mm
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C
73.75 mm
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D
63.75 mm
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Solution

The correct option is A 93.75 mm
Moment of inertia,
I=bh312=120×(750)312=42.1875×108mm4
Maximum deflection in the beam is given by
δ=5384wL4EI
=5384×120×103103×(15×103)4200×103×42.1875×108
=93.75 mm

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