A steel block $(100 m m \times 50 m m \times 50 m m)$ is subjected to a hydrostatic pressure $P = 200 M P a$ . Determine the magnitude of change in volume $(i n m m^{3})$ Use E = 200GPa $μ = 0.3$ .
300

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Solution

The correct option is A 300
$\frac{δ V}{V} = \frac{3 σ}{E} (1 - 2 μ)$

$δ V = \frac{100 \times 50 \times 50 \times 3 \times 200}{200 \times 10^{3}} (1 - 2 \times 0.3) = 300$

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A steel block (100 mm×50 mm×50 mm) is subjected to a hydrostatic pressure P=200 MPa. Determine the magnitude of change in volume (in mm3) Use E = 200GPa μ=0.3.300

The correct option is A 300δVV=3σE(1−2μ) δV=100×50×50×3×200200×103(1−2×0.3)=300

A steel block $(100 m m \times 50 m m \times 50 m m)$ is subjected to a hydrostatic pressure $P = 200 M P a$ . Determine the magnitude of change in volume $(i n m m^{3})$ Use E = 200GPa $μ = 0.3$ .
300

The correct option is A 300
$\frac{δ V}{V} = \frac{3 σ}{E} (1 - 2 μ)$

$δ V = \frac{100 \times 50 \times 50 \times 3 \times 200}{200 \times 10^{3}} (1 - 2 \times 0.3) = 300$