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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

A steel meter...

Question

A steel meter scale is to be ruled so that millimeter intervals are accurate within about $5 \times 10^{- 5} m m$ at a certain temperature. The maximum temperature variation allowable during the ruling is (Coefficient of linear expansion of steel $= 10 \times 10^{- 6} K^{- 1}$ )

2^{\circ}

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5^{\circ}

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7^{\circ}

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10^{\circ}

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Solution

The correct option is B $5^{\circ}$ C
In this case, change in length is allowed to be $5 \times 10^{- 5}$ mm
Length of $1$ division $= 1$ mm
$α = 10 \times 10^{- 6} d t$
putting all the values we get value of maximum temperature variation ( $d t$ ) as $5^{0}$ C

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Similar questions

Q. A steel metre scale is to be ruled so that the millimetre intervals are accurate within about

5 \times 10^{- 5} m m

at a certain temperature. The maximum temperature variation allowable during the ruling of the millimetre marks is (

α

for steel

= 11 \times 10^{- 6}^{o} C^{- 1}

)

Q. A steel scale is to be prepared such that the millimeter intervals are to be accurate within

6 \times 10^{- 5} m m

. The maximum temperature variation from the temperature of calibration during the reading of the millimeter marks is

(α = 12 \times 10^{- 6} /^{\circ} C)

Q. A meter scale made of steel reads accurately at

20^{\circ} C .

In a sensitive experiment

,

distances accurate up to

0.055 m m

1 m

are required

.

Find the range of temperature in which the experiment can be performed with this metre scale

.

Coefficient of linear expansion of steel

= 11 \times 10^{- 6}^{\circ} C .

A meter scale of steel is calibrated at to $20^{\circ} C$ give a correct reading.F ind the distance between 50 cm mark and 51 cm mark if the scale is used at $10^{\circ} C$ . Coefficient of linear expansion of steel is ${1.1 \times 10^{- 5}}^{\circ} C^{- 1}$

A barometer reads 75.0 cm on a steel scale. The room temperature is $30^{\circ} C$ . The scale is correctly graduated for $0^{\circ} C$ . The coefficient of linear expansion of steel is $α$ = $1.2 \times 10^{- 5} /^{\circ} C$ and the coefficient of volume expansion of mercury is $γ$ = $1.8 \times 10^{- 4} /^{\circ} C$ . Find the correct atmospheric pressure.

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A steel meter scale is to be ruled so that millimeter intervals are accurate within about 5×10−5 mm at a certain temperature. The maximum temperature variation allowable during the ruling is (Coefficient of linear expansion of steel=10×10−6 K−1)

The correct option is B 5∘ CIn this case, change in length is allowed to be 5×10−5 mmLength of 1 division =1 mmα=10×10−6dtputting all the values we get value of maximum temperature variation (dt) as 50C

A steel meter scale is to be ruled so that millimeter intervals are accurate within about $5 \times 10^{- 5} m m$ at a certain temperature. The maximum temperature variation allowable during the ruling is (Coefficient of linear expansion of steel $= 10 \times 10^{- 6} K^{- 1}$ )

The correct option is B $5^{\circ}$ C
In this case, change in length is allowed to be $5 \times 10^{- 5}$ mm
Length of $1$ division $= 1$ mm
$α = 10 \times 10^{- 6} d t$
putting all the values we get value of maximum temperature variation ( $d t$ ) as $5^{0}$ C