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Archimedes' Principle

A steel of le...

Question

A steel of length $5 c m$ can stay afloat on water. Find the weight of the needle. [Surface tension of water $= 0.07 N / m$ ]

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Solution

T=0.07 N/n
l=5 cm= 0.05 m
The weight of theneedle=upward force due to the surface tension=Tx(2l)=0.07x2x0.05=0.007m

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