Question

A steel plate is exposed to solar heat flux of $800\frac{W}{m^2}$ on one side. The plate is exposed to air at ${30}^{\circ }C$ on both sides. The convective heat transfer coefficients is $10\frac{W}{m^{2}K}$ on the back side and $15\frac{W}{m^{2}K}$ on the front. The equilibrium temperature of plate is

• A. ${44}^{\circ }C$
• B. ${86}^{\circ }C$
• C. ${62}^{\circ }C$
• D. ${36}^{\circ }C$

Answer 1

The correct option is C ${62}^{\circ }C$

$800\frac{W}{m^2}{T}_d={30}^{\circ }C$

$h_1=10\frac{W}{m^{2}K}{h}_2=15\frac{W}{m^{2}K}800=h_1(T-T_a)+h_2(T-T_a)800=10(T-30)+15(T-30)T={62}^{\circ }C$