A steel rod of cross section 1 mm2 is prevented from expansion by heating through 10- C- The thermal force developed in it is - Y - 2 - 1011 N-m2- - - 10-5 -C

The correct option is C 20N Δ LL =αΔ T= 10^ 5× (10 0) = 10^ 4 F = YAαΔ T=2 × 10^11×( 1 × 10^ 6) × #160; 10^ 4 =20 N ...

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Byju's Answer

Standard XII

Physics

Longitudinal Strain

A steel rod o...

Question

A steel rod of cross section 1 $m m^{2}$ is prevented from expansion by heating through $10^{\circ} C$ . The thermal force developed in it is :
$(Y = 2 \times 10^{11} N / m^{2}; α = 10^{- 5} /^{\circ} C)$

20N

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200 N

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0.2 N

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Solution

The correct option is C 20N
$\frac{Δ L}{L} = α Δ T = 10^{- 5} \times (10 - 0) = 10^{- 4}$
$F = Y A α Δ T = 2 \times 10^{11} \times (1 \times 10^{- 6}) \times 10^{- 4} = 20 N$

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A steel rod of cross section 1 mm2 is prevented from expansion by heating through 10∘C. The thermal force developed in it is :(Y=2×1011N/m2;α=10−5/∘C)

The correct option is C 20NΔLL=αΔT=10−5×(10−0)=10−4F=YAαΔT=2×1011×(1×10−6)×10−4=20N

A steel rod of cross section 1 $m m^{2}$ is prevented from expansion by heating through $10^{\circ} C$ . The thermal force developed in it is :
$(Y = 2 \times 10^{11} N / m^{2}; α = 10^{- 5} /^{\circ} C)$

The correct option is C 20N
$\frac{Δ L}{L} = α Δ T = 10^{- 5} \times (10 - 0) = 10^{- 4}$
$F = Y A α Δ T = 2 \times 10^{11} \times (1 \times 10^{- 6}) \times 10^{- 4} = 20 N$