A steel rod of length 1 m is heated from 25∘C to 75∘C keeping its length constant. The longitudinal strain developed in the rod is (Given: Coefficient of linear expansion of steel =12×10−6/∘C)n×10−4 . Report n.
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Solution
Strain developed: ∈=αΔT=(12×10−6)(50)=6×10−4
Strain will be negative, as the rod is in a compressed state.
Why this question?
Key Concept: Strain without changing length- yes, that is possible by changing physical conditions.
Caution: The length not changing does not imply 0 strain.