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Question

A steel tape 1m long is correctly calibrated for a temperature of 27.0 °C. The length of a steel rod measured by this tape is found to be 63.0 cm on a hot day when the temperature is 45.0 °C. What is the actual length of the steel rod on that day ? What is the length of the same steel rod on a day when the temperature is 27.0 °C ? Coefficient of linear expansion of steel = 1.20 × 10¯⁵ K¯¹ .

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Solution

Since the tape has been calibrated for 27 o Cso on the day when temperature is 27 o C no change in division of length has been observed.

When the temperature increases to 45 o C ( ΔT=4527=18 o C ), the increase observed in length of 1cmdivision of the scale is,

Δl=αlΔT

Where α=1.2× 10 5 K -1 , l=1cm

Substitute the values, then

Δl=1.2× 10 5 ×1×18=0.000216cm

So the length of 1cmdivision on tape becomes, 1+0.000216=1.000216cm.

Since the actual length of the rod is 63cm, therefore at day when temperature is 45 o C =63×1.000216=63.0136cm.

Actual length of the rod is same as 63cmat day when temperature is 27 o C, as the division of the steel tape does not change.


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