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Question

A steel tape is calibrated at 20C. It is used to measure a length of an object on a hot summer day when the temperature is 40C. If measured length is 5 m, the actual length is(a=1×105/C )

A
5.001m
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B
5.01 m
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C
5.1 m
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D
4.99 m
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Solution

The correct option is A 5.001m
The scale is calibrated at 200C
At 400C , the measuring gaps will be more. So, it will measure lesser than the actual.
Using, l2=l1(1+αdt) where α=105, dt = 20 and l1 = 5, we get l2 = 5.001m

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