A steel vessel of capacity 22.4 litres contains 2 $g$ of $H_{2}$ , 8 $g$ of $O_{2}$ and 22 $g$ of $C O_{2}$ at $0^{o} C$ temperature. The total pressure of the mixture is:

3.5

a t m

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5.25

a t m

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1.75

a t m

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4.0

a t m

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Solution

The correct option is C $1.75$ $a t m$
$n = n_{1} + n_{1} + n_{3}$
$P = \frac{n R T}{V}$
$n_{H_{2}} = 1, n_{O_{2}} = 0.25, n_{C O_{2}} = 0.5, V = 22.4$ $l$ , $T = 273$ $K$
$P = 1.75$ $a t m$

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A steel vessel of capacity 22.4 litres contains 2 g of H2 , 8 g of O2 and 22 g of CO2 at 0oC temperature. The total pressure of the mixture is:

The correct option is C 1.75 atmn=n1+n1+n3P=nRTVnH2=1,nO2=0.25,nCO2=0.5,V=22.4 l, T=273 KP=1.75 atm

A steel vessel of capacity 22.4 litres contains 2 $g$ of $H_{2}$ , 8 $g$ of $O_{2}$ and 22 $g$ of $C O_{2}$ at $0^{o} C$ temperature. The total pressure of the mixture is:

The correct option is C $1.75$ $a t m$
$n = n_{1} + n_{1} + n_{3}$
$P = \frac{n R T}{V}$
$n_{H_{2}} = 1, n_{O_{2}} = 0.25, n_{C O_{2}} = 0.5, V = 22.4$ $l$ , $T = 273$ $K$
$P = 1.75$ $a t m$