A steel wire 2m long is suspended from the ceiling. When a mass is hung at its lower end, the increase in length recorded is 1cm. Determine the strain in the wire.
A
5×10−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5×10−3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.5×10−3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.5×10−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B5×10−3 Given,
Original length =2m
Increase in length =1cm=1×10−2m
Longitudinal strain =Increase in lengthOriginal length=ΔLL =1×10−2m2m=5×10−3