A steel wire fixed at both ends has a fundamental frequency of $200$ Hz. A person can hear sound of maximum frequency $15$ k Hz. What is the highest harmonic that can be played on this string which is audible to the person?

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Solution

We know,
In case of,
Wave in string clamped at both ends,

Frequency of $n^{t h}$ harmonic $= n f_{0}$

Here,

$n f_{0} \leq 15000$

$n \leq \frac{15000}{200} = 75$

Highest $75^{t h}$ harmonic can be played and is audible.

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A steel wire fixed at both ends has a fundamental frequency of 200 Hz. A person can hear sound of maximum frequency 15k Hz. What is the highest harmonic that can be played on this string which is audible to the person?

We know,In case of,Wave in string clamped at both ends,Frequency of nth harmonic=nf0Here,nf0≤15000n≤15000200=75Highest 75th harmonic can be played and is audible.

A steel wire fixed at both ends has a fundamental frequency of $200$ Hz. A person can hear sound of maximum frequency $15$ k Hz. What is the highest harmonic that can be played on this string which is audible to the person?

We know,
In case of,
Wave in string clamped at both ends,

Frequency of $n^{t h}$ harmonic $= n f_{0}$

Here,

$n f_{0} \leq 15000$

$n \leq \frac{15000}{200} = 75$

Highest $75^{t h}$ harmonic can be played and is audible.