A steel wire of a length 2l and crossectional area 'a' stretched in the within the elastic limit. calculate the stain in the wire

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Solution

Tensile force, $F$

Area, $a$

Tensile Yield strength, = $T$

Young modulus, $= Y$

Length, $2 L$

$s t r a i n = \frac{s t r e s s}{y o u n g modulus} = \frac{T}{Y} = \frac{F}{a Y}$

Hence, strain is $\frac{F}{a Y}$

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A steel wire of a length 2l and crossectional area 'a' stretched in the within the elastic limit. calculate the stain in the wire

Tensile force, F Area, a Tensile Yield strength, =T Young modulus, =Y Length, 2L strain=stressyoungmodulus=TY=FaY Hence, strain is FaY

Tensile force, $F$

Area, $a$

Tensile Yield strength, = $T$

Young modulus, $= Y$

Length, $2 L$

$s t r a i n = \frac{s t r e s s}{y o u n g modulus} = \frac{T}{Y} = \frac{F}{a Y}$

Hence, strain is $\frac{F}{a Y}$