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Byju's Answer
Standard XII
Physics
Young's Modulus of Elasticity
A steel wire ...
Question
A steel wire of diameter
1
×
10
−
3
m
is stretched by a force of
20
N
. Calculate the strain energy per unit volume. (
Y
steel
=
2
×
10
11
N
/
m
2
)
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Solution
Given
d
=
1
×
10
−
3
m
,
F
=
20
N
Y
=
2
×
10
11
N
/
m
2
,
r
=
d
2
=
0.5
×
10
−
3
m
=
5
×
10
−
4
m
∴
Cross sectional area
A
=
π
r
2
=
3.142
×
25
×
10
−
8
m
2
Strain energy per unit volume of the wire
=
1
2
Y
(
s
t
r
e
s
s
)
2
=
(
F
/
A
)
2
2
Y
=
F
2
2
A
2
Y
=
(
20
)
2
2
×
(
3.142
×
25
×
10
−
8
)
2
×
2
×
10
11
=
1622
J
/
m
3
.
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