A steel wire of length $30 c m$ is stretched ti increase its length by $0.2 c m$ . Find the lateral strain in the wire if the poisson's ratio for steel is $0.19$ :

0.0019

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0.0008

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0.019

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0.008

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Solution

The correct option is A $0.0019$
Poisson's ratio $= - \frac{ϵ_{l a t e r a l}}{ϵ_{L o n g t u d i n a l}}$
$ϵ_{l o n g i t u d i n a l} = \frac{△ L}{L} = \frac{0.2}{20}$
$∴ ϵ_{l a t e r a l} = - \frac{0.2}{20} \times 0.19$
$= - 0.0019$
$| ϵ_{l a t e r a l} | = 0.0019$

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